Is 9 40 41 a pythagorean triple?

No, the numbers 9, 40, and 41 do not form a Pythagorean triple. To be a Pythagorean triple, the equation (a^2 + b^2 = c^2) must hold true, where (c) is the largest number. In this case, (9^2 + 40^2 = 81 + 1600 = 1681), and (41^2 = 1681), so (9^2 + 40^2 = 41^2). Therefore, 9, 40, and 41 do form a Pythagorean triple.