Two batsmans each on 94 7 runs required to win in 3 balls both make unbeaten 100 how?

1st Ball : First Batsman Hit a Dil-Scoop to a Wicket Keepers Helmet on the Field. then get 5 runs for it.

2nd Ball : First Bats Man get a 1 run then he reaches 100.

3rd Ball : 2nd Batsman Hit a six Both Scored 100 and match win

====================================================

1st BALL : ONE BATSMAN HIT A FOUR.

2nd Ball : same batsman make a shot and take three runs but onje run is short and it will be counted as 2 runs.

3rd Ball : the other batsman hit a SIX and won the match.

Both are at unbeaten 100.

Also the case is the overs might be reduced to 48.2 overs or 48.1 overs something then both batsman can hit a SIX

http://www.orkut.co.in/Profile.aspx?uid=14944937969814434926

Ball1:Batsman1(94) hit six , completes his 100 and retired hurt because of injury.

Two balls and One run to win.

Ball2:New Batsman(0) tries to take single and run out. Batsman2(94) at the striker end and non striker end got replaced by the retired hurt batsman.

One ball and One run to win.

Ball3:Batsman2(94) hit six and completes his 100.

Both unbeaten at 100 and Match Won.

Note: It's mentioned that in case the ball hits the keeper's helmet the ball maybe called a dead ball. Not sure on this one but even if it is called a dead ball still this answer holds true.