At its max height 0.490m its velocity is 0
therefore we can use the equation of motion that
v^2 = u^2 + 2as
u^2 = 0 - 2 x -9.80(negavtive for direction) x 0.490
therefore u^2 = 7.644
= root 7.644
initial velocity = 2.76 m/s to 2 decimal places
hope it helps
To calculate the time you can use another equation of motion
t = (v-u)/a
substitute in :
0-2.76/-9.8
= 0.28seconds
but that's only half the journey to its maximum point therefore the time to reach back to the starting point is double this as the acceleration is the same
so the answers 0.56 seconds - im sure lol
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