If f(x) x2 and ndash 2x and g(x) 6x plus 4 for which value of x does (f plus g)(x) 0?

To find the value of ( x ) for which ( (f + g)(x) = 0 ), we first need to define the functions: ( f(x) = x^2 - 2x ) and ( g(x) = 6x + 4 ). Then, we combine them:

[ (f + g)(x) = x^2 - 2x + 6x + 4 = x^2 + 4x + 4. ]

Next, we set this equal to zero:

[ x^2 + 4x + 4 = 0. ]

Factoring gives ( (x + 2)^2 = 0 ), leading to ( x = -2 ) as the solution.