There are many ways, but here is one.
Example:
A. x2 + 5x + 6
coefficients: 1, 5, 6
You have to find two numbers that the two ends multiply to get the sum of the middle coefficient in the order of ax2 + bx + c (read on to understand)
1 x 6 = 6
Find two numbers that multiply to 6, but add to 5
1 6 : 1 x 6 = 6, 1 + 6 = 7 X
2 3 : 2 x 3 = 6, 2 + 3 = 5 <---
So, the special numbers are 2 and 3.
Now, add them into this: (x+_)(x+_)
Both are positive, so it works! (x+2)(x+3)
Let's check.
(x+2)(x+3)
Use FOIL Method (first, outer, inner, last)
= x2 + 2x + 3x + 6
= x2 + 5x + 6
It works! Now, if you have trouble understanding, reread it a few times, and you'll get it in a blink!
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