How do you find five consecutive number whose sum is 465?

Let the number be represented by 'a'

a+(a+1)+(a+2)+(a+3)+(a+4)=465

a+a+1+a+2+a+3+a+4=465

a+a+a+a+a+1+2+3+4=465

5a+10=465

5a=465-10

5a=455

5a/5=455/5

a=91

So if a=91

a+1=92

a+2=93

a+3=94

a+4=95