What is the second number of the sum of four consecutive odd integers 28458968?

Four consecutive odd integers: [2x-1], [2x+1], [2x+3], [2x+5].

Their sum: (2x-1) + (2x+1) + (2x+3) + (2x+5) = 8x + 8 = 8(x+1) = 28,458,968

(x+1) = 28,458,968/8 = 3,557,371

x = 3,557,370

The numbers are:

7,114,739

=> 7,114,741 <=

7,114,743

7,114,745

Check: The sum of this list is 28,458,968 Yay!