To find the probability of the remaining ball being red after removing four balls, we first consider the total combinations of removing four balls from the box containing three red and two black balls. The only possible scenario where a red ball remains is if at least one red ball is not removed. Given that there are three red balls, the probability of removing all four balls as red is impossible. Hence, the probability of at least one red ball remaining is certain, making the probability of the remaining ball being red effectively (1) or (100%), assuming that we only have a single ball left in the box.
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