Integral of sec2x-cosx plus x2dx

I wasn't entirely sure what you meant, but if the problem was to find the integral of [sec(2x)-cos(x)+x^2]dx, then in order to get the answer you must follow a couple of steps:

• First you should separate the problem into three parts as you are allowed to with integration. So it becomes the integral of sec(2x) - the integral of cos(x) + the integral of x^2
• Then solve each part separately

The integral of sec(2x) is -(cos(2x)/2)

The integral of cos(x) is sin(x)

The integral of x^2 is

• Lastly you must combine them together:

-(cos(2x)/2) - sin(x) + (x^3)/3