How many liters of ammonia gas can be formed when 100 g hydrogen gas are completely reacted with nitrogen gas to form ammonia gas at stp?

To find out how many liters of ammonia gas can be formed from 100 g of hydrogen gas, we first calculate the number of moles of hydrogen: ( \text{moles of H}_2 = \frac{100 , \text{g}}{2 , \text{g/mol}} = 50 , \text{mol} ). The balanced equation for the formation of ammonia is ( N_2 + 3H_2 \rightarrow 2NH_3 ), indicating that 3 moles of hydrogen produce 2 moles of ammonia. Therefore, 50 moles of hydrogen will produce ( \frac{2}{3} \times 50 = 33.33 , \text{mol} ) of ammonia. At STP, 1 mole of gas occupies 22.4 liters, so the volume of ammonia produced is ( 33.33 , \text{mol} \times 22.4 , \text{L/mol} \approx 748.8 , \text{L} ).