Can anyone solve x plus 2y equals 8 and 3x-2y equals 8 as a simultaneous equation and show their working?

x+2y=8 Here you must add the expressions (2y - 2y = 0)

3x-2y=8

4x=16 Now you are left with a multiple of x so you can simply divide by 4

x=4 on both sides of the =

4+2y=8 Now you substitute x=4 into one of the original equations to find y

2y=4

y=2

Hope this helped.