What is the n factor of FeS2?

The n factor of FeS2 (iron(II) disulfide) can be determined based on its oxidation states. In FeS2, iron (Fe) has an oxidation state of +2, while each sulfur (S) has an oxidation state of -1. The n factor is the total change in oxidation states per formula unit, which is calculated as the sum of the positive and negative charges: n factor = 2 (from Fe) + 2 (-1 from each S) = 0. Therefore, the n factor of FeS2 is 4, reflecting the total change in oxidation states when it reacts.