What does a hollow 8x8x16 block weight filled with concrete and reinforcing?

The volume of a 8inx8inx16in block is 1024in^3 or .59259ft^3. I would assume that steel is used for the reinforcing. The density of steel varies from 484 to 503 lb/ft^3 and the density of concrete varies from 109.25 to 149.83 lb/ft^3. So assuming that the steel reinforcement accounts for 6% of the volume then the weight of the steel would be greater than 17.21lbs (.59259ft^3*0.06*484lb/ft^3) and less than 17.88lbs (.59259ft^3*0.06*503lb/ft^3). The concrete would then account for 94% of the volume and its weight would be greater than 60.86lbs (.59259ft^3*0.94*109.25lb/ft^3) and less than 83.46lbs (.59259ft^3*0.94*149.83lb/ft^3). So with all of these assumptions the block would weigh between 78.07 and 101.34lbs.