To find the value of ( \log(0.000002) ), we can express it in scientific notation as ( 2 \times 10^{-6} ). Using the properties of logarithms, ( \log(0.000002) = \log(2) + \log(10^{-6}) ). Since ( \log(10^{-6}) = -6 ) and ( \log(2) ) is approximately 0.301, we have ( \log(0.000002) \approx 0.301 - 6 ), which gives us approximately -5.699.
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