The length of a rectangle is 2in more than twice its width and the perimeter of the rectangle is 16in find the width of the rectangle?

Using algebra to solve this geometric problem, call the width w inches long.

Therefore the length is 2w+2 inches (i.e. "2in more than twice its width").

There are two widths and two lengths in the perimeter so now add them up. w+w+2w+2+2w+2=6w+4 The perimeter is equal to 16 inches, so 6w+4=16 6w=12 w=2 inches