The perimeter of a rectangular garden is 52 feet The length of the garden is 4 feet less than twice the width What is the width of the garden?

To solve this problem using algebraic equations :

Set the variable x as the width of the garden

The length of the garden becomes 2x - 4 (4 feet less than twice X).

The perimeter is equal to twice the length plus twice the width P = 2L + 2W

and has the value 52 feet.

Substituting the terms for length and width,

52 = 2 L + 2 W so 2(2x-4) + 2(x) = 52

2(2x-4) + 2 (X) = 52

4x - 8 + 2x = 52

6x = 60

x = 10 and 2x-4 = 16

The width is 10 feet, the length is 16 feet.

Verifying, you have 10+10+16+16 = 52