How many joules of energy are necessary to melt 46.0 grams of ice?

To calculate the energy required to melt ice, we use the formula ( Q = m \cdot L_f ), where ( Q ) is the heat energy, ( m ) is the mass of the ice, and ( L_f ) is the latent heat of fusion for ice, approximately 334 joules per gram. For 46.0 grams of ice, the energy required would be ( Q = 46.0 , \text{g} \times 334 , \text{J/g} ), which equals about 15,364 joules. Therefore, approximately 15,364 joules are necessary to melt 46.0 grams of ice.