The equation for this reaction is 3 Ca + N2 -> Ca3N2. The gram molecular mass of Ca3N2 is 148.25, and the gram Atomic Mass of Ca is 40.08. Therefore, the amount of Ca3N2 that could theoretically be formed from 56 grams of calcium is 56(148.25)/(3 X 40.08) or 69.10 grams. The percentage yield is therefore 100(32)/(69.10) or 46 %, to the justified number of significant digits.
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