What is the mass of 0.7891 mol of ferric oxide (Fe2O3)?

Atomic Mass of Fe: 55.8g/mol

Atomic Mass of O: 16g/mol

Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol

mass = Molecular mass x number of moles

mass = 159.6g/mol x 0.7891mol = 125.94g