The formula you are looking for is I = E/R. Amps = Volts/Resistance.
If you say it is normally a 2 Amp circuit, it normally draws 2 amps.
Therefore the original resistance offered to the 12v battery is 2/12 = 6 Ohms.
If you then connect a 12 Ohm resistor in series, they are added, so R = 18 Ohms.
Now if you put 12v across this circuit it will draw 12/18 = 0.66 Amps.
Or
If you just put a 12 Ohm resistor across the 12v supply it will draw 1 Amp.
If the circuit is protected by a 2 Amp fuse, it will not blow, but the resistor will get hot.
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