Potassium fluoride (KF) a salt has a molecular weight of 58.10 grams. How many grams would be needed to mix 1.0 liter of 0.10 M salt solution?

To calculate the grams needed to mix a 0.10 M potassium fluoride solution, you would first find the molar mass of KF (58.10 g/mol). Then use the formula Molarity = moles/Liter to find the moles of KF needed (moles = Molarity x Volume). Finally, convert moles to grams using the molar mass: grams = moles x molar mass. In this case, you would need 5.81 grams of KF to make a 0.10 M solution in 1.0 liter.