What is the total number of grams of NaI(s) needed to make 1 L of a 0.010M solution?

To make a 0.010M NaI solution, you'll need 0.010 moles of NaI per liter. The molar mass of NaI is 149.89 g/mol. Therefore, to calculate the grams needed, you would multiply the molar mass by the number of moles, which gives you 1.499 g of NaI needed per liter of solution.