How do you find the area between the curves y24x and y2x using integration?

You need to be more accurate and precise in submitting problems of this nature. Regardless, I think I have it figured out. The functions

Y2 = 4X

Y = 2X

To find area here you need bounds. The graph admits of only these bounds; 0 to 1. Y2 = 4X is the top function.

Rewrite.

Y2 = 4X

Y = sqrt(4X)

Y = 4X 1/2

------------------integrate

int( 4X 1/2 - 2X) dx

= (8/3)X 3/2 - X2

----------------------------------insert bounds

(8/3)(1) 3/2 - (0)2

= 8/3

======the area between these functions