How many 5 letter's passwords can be formed from the letters payment if no repetition of letters is allowed?

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1078764

2026-04-06 07:25

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The Word "payment" has 7 distinct letters: p, a, y, m, e, n, t. To form a 5-letter passWord without repetition, we can choose the first letter in 7 ways, the second in 6 ways, the third in 5 ways, the fourth in 4 ways, and the fifth in 3 ways. Thus, the total number of 5-letter passWords is given by the permutation formula ( P(7, 5) = 7 \times 6 \times 5 \times 4 \times 3 = 2520 ).

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