What is the size of an exterior angle in a hendecagon?

The sum of the exterior angles of a polygon is 360o.

For a regular polygon, each exterior angle is the same, thus

number_of_sides x exterior_angle = 360o

⇒ exterior_angle = 360o ÷ number_of_sides.

A hendecagon has 11 sides, thus:

exterior_angle = 360o ÷ 11 = 328/11o ~= 32.7o

⇒