One kilocalorie of heat energy will raise temp of water how many degrees celsius?

Change in temperature, dT,=1/m, where m is the amount of water, in kilograms.

Depends on how much kilograms of water you have. The equation to use is Q=cm(dT), where c is the specific heat capacity of water (conventional use puts it 4186 J/(kg*C degrees)), m is the mass, in kilograms, of the water you're heating, dT is the amount of degrees, in Celsius (or Kelvin), that you want to heat the water by, and Q is the amount of energy needed, in Joules. 1 kilocalorie equals 4186J, solving for change in temperature (dT), dT=Q/(cm). Substituting in Q and c gives you dT=1/m. If you do not know the mass, but only volume, m=pV, where p is the density of water (convetionally 1 *10^3 kg/m^3) and V is the volume of the amount of water you have in m^3.