To determine the voltage required for an x-ray tube to emit x-rays with a minimum wavelength of 30 picometers (pm), we can use the formula ( E = \frac{hc}{\lambda} ), where ( h ) is Planck's constant, ( c ) is the speed of light, and ( \lambda ) is the wavelength. The energy ( E ) in electron volts (eV) corresponds to the voltage ( V ) applied to the x-ray tube, since ( E = eV ). For a minimum wavelength of 30 pm, the required voltage is approximately 41.3 MeV, which is equivalent to 41,300,000 V.
Copyright © 2026 eLLeNow.com All Rights Reserved.