Fructose would be expected to form a red color with Selivanoff's reagent, while glucose would not. This is because Selivanoff's reagent differentiates between aldoses and ketoses; fructose, a ketose, reacts quickly to give a red color, whereas glucose, an aldose, reacts more slowly and typically yields a different result. Therefore, the rapid formation of a red color indicates the presence of fructose.
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