What is the width of an octagon if all the sides are 6 feet?

To find the width of a regular octagon with each side measuring 6 feet, you can use the formula for the width (also known as the "diameter of the circumscribed circle") of a regular octagon, which is approximately 2.414 times the length of one side. Thus, the width would be about 2.414 × 6 feet, equating to approximately 14.48 feet.