When calculating oxidation numbers, use '-2' (oxygen) as the 'yardstick'(standard).
Since SO3 has three oxygens, then the oxygen moiety is 3 x -2 = -6
Since SO3 is a neutrally charged molecule, overall oxidation is '0'.
Hence
S + -6 = 0
Hence S = 6 is the oxudation number for sulphur.
NB Sulphur exhibits different oxidation states in different molecules.
S = 0
SO2 = 4
SO3 = 6 ( as above)
H2SO4) = 6
H2S2O7 (Oleum) = 6
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