What is the molality of a solution made by dissolving 6 miles of NaOH in 3 kg of water?

Molality (m) is calculated using the formula ( m = \frac{\text{moles of solute}}{\text{mass of solvent in kg}} ). In this case, you have 6 moles of NaOH and 3 kg of water. Therefore, the molality of the solution is ( m = \frac{6 \text{ moles}}{3 \text{ kg}} = 2 \text{ mol/kg} ). Thus, the molality of the NaOH solution is 2 molal.