WHAT HAPPENS TO THE POWER OF THE RESISTANCE CONNECTED TO A BATTERY IS CUT IN HALF?

If the resistance connected to a battery is cut in half, the current flowing through the circuit will increase, following Ohm's Law (I = V/R). Since the voltage (V) from the battery remains constant, halving the resistance (R) results in doubling the current (I). Consequently, the power dissipated in the circuit, calculated using the formula P = I²R, will increase, as the increase in current outweighs the decrease in resistance. Overall, the total power consumed by the circuit will rise.