What the height of a baseball with a mass of a 0.15 kg that has a GPE of 73.5 J?

Recall E = m c^2

m = 0.15 kg = 0.15 kg

c = 3 * 10^8 m/s

So c^2 = 9 * 10^16

Hence E = 0.15 * 9 * 10^16 = 1.35 * 10^16 J