What is the speed if A proton moving east experiences a force of 8.8x10-19 N upward. At this location the field has a magnitude of 5.5 x 10-5 T?

To find the speed of the proton, we can use the equation F = qvB, where F is the force, q is the charge of the proton, v is the velocity, and B is the magnetic field strength. Rearranging this equation gives us v = F / (qB). Plugging in the values, v = (8.8x10-19) / (1.6x10-19 * 5.5x10-5) = 1.0 m/s.