According to Kepler's third law the square of the planets period in years is?

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Answer

1083907

2026-04-17 03:30

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T^2 is proportional to r^3 (or a^3).

More exactly, T^2 = (2*pi)^2/(GM)*r^3 (or a^3).

Where...

  • T is the period
  • r is the radius of the orbit
  • a is the length of the semimajor axis of the orbit
  • pi is about 3.142
  • G is the gravitational constant 6.67x10^-11
  • M is the mass of the planet
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