Resistance is inversely-proportional to the cross-sectional area of a conductor. For example, doubling its cross-sectional area will halve its resistance, while halving its cross-sectional area will double its resistance.
Since the cross-sectional area of a circular-section conductor is proportional to the square of its radius, doubling that radius will reduce its resistance by one quarter, while halving its radius will quadruple its resistance.
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