What is another division problem with 3 and remainder 28?

To find another division problem that results in a quotient of 3 and a remainder of 28, you can use the formula: ( \text{dividend} = (\text{divisor} \times \text{quotient}) + \text{remainder} ). Here, if we let the divisor be 10, the calculation would be ( 10 \times 3 + 28 = 30 + 28 = 58 ). Thus, ( 58 \div 10 ) gives a quotient of 3 and a remainder of 28.