What is the molality of a solution that has 3 mol of glucose in 6kg of water?

Molality (m) is calculated using the formula ( m = \frac{\text{moles of solute}}{\text{kg of solvent}} ). In this case, there are 3 moles of glucose and 6 kg of water. Therefore, the molality of the solution is ( m = \frac{3 , \text{mol}}{6 , \text{kg}} = 0.5 , \text{mol/kg} ). Thus, the molality of the solution is 0.5 mol/kg.