The balanced chemical equation for the breakdown of sodium bicarbonate (NaHCO3) is:
2 NaHCO3 -> Na2CO3 + CO2 + H2O
From this equation, it can be seen that one mole of NaHCO3 produces one mole of H2O. The molar mass of NaHCO3 is 84 g/mol. Therefore, 168 g of NaHCO3 will produce 84 g of H2O.
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