How much heat is liberated (in kJ) from 252 g of silver when it cools from 89.5 C to 26.3 C?

To answer this question, you need to know the heat capacity (C) for silver (Ag). It happens to be 0.240 J/g/deg. Then you can use the formula q = mC∆T where q = heat; m = mass; C = sp.heat cap; ∆T = change in temp. q = (252 g)(0.240 J/g/deg)(63.2 deg) = 3822 Joules