When crossing two heterozygous pea plants (Yy x Yy) using a Punnett square, the resulting genotypes are YY, Yy, Yy, and yy. This results in a 1:2:1 genotype ratio, where 25% of the offspring will be homozygous dominant (YY), 50% will be heterozygous (Yy), and 25% will be homozygous recessive (yy). The phenotypic ratio will be 3 yellow (YY and Yy) to 1 green (yy).
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