In a random sample of 144 observations the sample proportion equals 0.6 The 95 percent confidence interval for P is?

95% CI for Proportion is p +/- E; where E = Z*sqrt(p*q/n). P=.6, q=.4, n=144, Z=1.96. Therefore E=1.96*sqrt(0.4*0.6/144) = 0.08. So, 95% CI = .6 +/- 0.08 or .52 to .68.