What is the straight line equation that has a slope of 1 over 3 and passing through a point of 2 and minus 5 on the line?

y = mx+c where m is the slope and c is the intercept on the y axis

So: 1/3*2+c = -5

c = -5-2/3

c = -17/3

Therefore: y = 1/3x-17/3 => 3y = x-17 which can be expressed as x-3y-17 = 0