What is the electron configuration for a lead 2 plus?

The electron configuration for lead (Pb), which has an atomic number of 82, is normally written as [Xe] 4f² 5d¹⁰ 6s² 6p². When lead is in the +2 oxidation state (Pb²⁺), it loses two electrons, typically from the 6p subshell. Therefore, the electron configuration for Pb²⁺ is [Xe] 4f² 5d¹⁰ 6s².