A compound of vanadium has a magnetic moment of 1.73 find the oxidation state of vanadium?

The magnetic moment of 1.73 μB suggests that the vanadium compound has one unpaired electron, which typically corresponds to a +4 oxidation state. Vanadium in the +4 oxidation state (V^4+) has the electron configuration of [Ar] 3d^1 4s^0, leading to one unpaired electron in the d-orbital. Therefore, the oxidation state of vanadium in this compound is +4.