What would be the dimensions of the rectangle if the length is yd more than twice the width the area is 452?

Let the length be 2x+1 and the width be x:-

And so: (2x+1) times x = 452 or 2x^2 +x -452 = 0

Using the quadratic equation formula x has a positive value of: 14.78537495

Width = 14.78537495 yds and length is 2*(14.78537495)+1 = 30.5707499 yds

Check: width times length = 451.9999998 which rounds to 452 square yards