When an inductor tunes at200Khz with 624pF capacitor and at 600Khz wth 60.4pF capacitor then the self capacitance of the inductor would be?

To find the self-capacitance of the inductor, we can use the resonant frequency formula ( f = \frac{1}{2\pi\sqrt{L(C + C_s)}} ), where ( C ) is the external capacitance and ( C_s ) is the self-capacitance of the inductor. By setting up equations for both resonant frequencies (200 kHz with 624 pF and 600 kHz with 60.4 pF), we can solve for ( C_s ). However, the precise calculation requires additional steps and numerical methods to isolate ( C_s ). Generally, the self-capacitance can be estimated by analyzing the two equations derived from the two frequencies and solving them simultaneously.