To find the voltage applied in the circuit, we can use the formula for power dissipation: ( P = V \times I ). Rearranging this gives ( V = \frac{P}{I} ). Given that the power ( P ) is 100 MW (or ( 100 \times 10^6 ) W) and the current ( I ) is 12.5 mA (or ( 12.5 \times 10^{-3} ) A), we can calculate the voltage as follows:
[ V = \frac{100 \times 10^6 \text{ W}}{12.5 \times 10^{-3} \text{ A}} = 8 \times 10^{12} \text{ V} = 8 \text{ teravolts}. ]
Thus, the applied voltage is 8 teravolts.
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