If a tire can hold 19 L of air at 175 kPa and 25 and deg Celsius what volume of air can the tire hold at 215 kPa and 30 and deg Celsius?

To find the new volume of air that the tire can hold at 215 kPa and 30°C, we can use the ideal gas law and the combined gas law. Since the number of moles of air in the tire remains constant, we can set up the ratio:

[(P_1 \times V_1) / T_1 = (P_2 \times V_2) / T_2]

Where:

• (P_1 = 175 , \text{kPa})
• (V_1 = 19 , \text{L})
• (T_1 = 25 + 273.15 = 298.15 , \text{K})
• (P_2 = 215 , \text{kPa})
• (T_2 = 30 + 273.15 = 303.15 , \text{K})

Rearranging for (V_2) gives:

[V_2 = V_1 \times \frac{P_1}{P_2} \times \frac{T_2}{T_1}]

Substituting the values yields approximately (V_2 \approx 17.6 , \text{L}).