How do you factor this. x2y2 plus 2x3y?

x^(2)y^(2) + 2x^(3) y

To factor

'x^(2) is common to both terms.

Hence

x^(2) [ y^(2) + 2xy]

'y' is common to both terms

Hence

x^(2)y[ y + 2x ] Fully factored.